sinx+siny+sinz=0
then what is sin3x+sin3y+sin3z=
Last Activity: 14 Years ago
sin3A = 3sinA - 4sin3A, x3+y3= (x+y)(x2-xy+y2)
sin3x +sin3y +sin3z= 3(sinx+siny+sinz)-4(sin3x+sin3y+sin3z) = -4((sinx+siny)3 -3sinxsiny(sinx+siny)+sin3z)
=-4((sinx+siny+sinz)((sinx+siny)2 +sin2z -sinz(sinx+siny)) +12sinxsiny(sinx+siny)=-12sinxsinysinz
'Win exciting gifts by answering the questions on Discussion Forum.'
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Get your questions answered by the expert for free
Last Activity: 2 Years ago
Last Activity: 3 Years ago