CosA-SinA+1/CosA+SinA-1=CosecA+CotA
CosA-SinA+1/CosA+SinA-1=CosecA+CotA
anshu rawat , 15 Years ago
Grade 11
Trigonometry> Trigonomentry...
1 Answers
swapnil sudhir
(cosA-sinA)+1/(cosA+sinA)-1
taking conjugate
(cosA-sinA)+1/(cosA+sinA)-1 * (cosA+sinA)+1/(cosA+sinA)+1
multiplying we get
=cos2A-sin2A+2cosA+1/2sinAcosA
=cos2A-sin2A+2cosA+sin2A+cos2A/2sinAcosA
on solving we get
=2cos2A+2cosA/2sinAcosA
=taking 2 common and divided
we get
=cosA+cos2A/sinAcosA
we can alsom write in the form of
cosA/sinAcosA +cos2A/sinAcosA
on solving we get
CosecA+cotA =R.H.S
by swapnil sudhir
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