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If in triangle ABC, AD is the altitude from A. given b>c, angle C =23degree & AD =abc / b^2-c^2. then angle B equal to?


If in triangle ABC, AD is the altitude from A. given b>c, angle C =23degree & AD =abc / b^2-c^2.


then angle B equal to?


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1 Answers

Askiitians Expert Soumyajit IIT-Kharagpur
28 Points
12 years ago

Dear Nehal,

Ans:- AD=c sinB=abc/(b² - c²)

             or sinB=ab/(b² - c²)

              or sinB=sinA sinB/sin(B+C) sin(B-C)

                or sinB=sinAsinB/sinAsin(B-C)

                or sin(B-C)=1=sin90°

                     or B-C=90°

                        Hence B=113°(ans)

 

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SOUMYAJIT IIT_KHARAGPUR

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