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# If in triangle ABC, AD is the altitude from A. given b>c, angle C =23degree & AD =abc / b^2-c^2.then angle B equal to?

Grade:

## 1 Answers

Askiitians Expert Soumyajit IIT-Kharagpur
28 Points
10 years ago

Dear Nehal,

Ans:- AD=c sinB=abc/(b² - c²)

or sinB=ab/(b² - c²)

or sinB=sinA sinB/sin(B+C) sin(B-C)

or sinB=sinAsinB/sinAsin(B-C)

or sin(B-C)=1=sin90°

or B-C=90°

Hence B=113°(ans)

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SOUMYAJIT IIT_KHARAGPUR

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