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sin-1 (x) = 2 tan-1(x). number of solutions are -
a) 1
b)2
c)3
d)5
sin-1 x=2tan-1 x or sin-1 x=sin-1 (2x/1+x2 ) . or x=2x/1+x2 . or x+x3 =2x . or x3 -x=0 . hence x=0,-1,1 are the solutions of the equation. . therefore, number of solutions are 3.
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