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Grade: 11
        
2)COS12 – SIN12 /CO12+SIN12 + SIN147/ COS147
  1. 1
  2. -1
  3. 0
  4. NONE
one year ago

Answers : (1)

Arun
15907 Points
							
Dear Krisha
 
[cos(90-78) - sin12/ cos(90-78) + sin12 ] + sin147/cos147]
 
= [sin78 - sin12]/[sin78 + sin12]  +sin(180-33)/cos(180-33)
 
= [(2 cos 45 sin 33)/(2 sin 45 cos33)] + sin 33/(-cos 33)
 
Since cos 45 = sin 45, hence they can be cancelled
 
= Sin 33/ cos33  - sin 33/cos33
= 0
 
Regards
Arun (askIITians forum expert)
11 months ago
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