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1/tan3a -tana -1/cot3a-cota answer this question please it`s very urgent

Aditi sngh , 9 Years ago
Grade 11
anser 1 Answers
Sai Rakshit
1/tan3A-tanA------------------------------------------------------(1)
1/cot3A-cotA=(tan3AtanA)/(tan3A-tanA)----------------(2)
              bya adding (1) and (2)
  (1+tan3AtanA)/(tan3A-tanA)                                                      formulatan(a-b)=(tana-tanb)/(1+tanatanb)
  1/tan2A=cot2A-----------------------------------(answer)
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Last Activity: 9 Years ago
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