Sai Rakshit
Last Activity: 8 Years ago
1/tan3A-tanA------------------------------------------------------(1)
1/cot3A-cotA=(tan3AtanA)/(tan3A-tanA)----------------(2)
bya adding (1) and (2)
(1+tan3AtanA)/(tan3A-tanA) formula = tan(a-b)=(tana-tanb)/(1+tanatanb)
1/tan2A=cot2A-----------------------------------(answer)