Trigonometry

(1+tan1°)(1+tan2°)..................(1+tan45°)=2^n
Find value of n?

Question image for (1+tan1°)(1+tan2°)..................(1+tan45°)=2^

Imran Khan

8 Years agoGrade

1 Answer

Arun

Approved Tutor Answer8 Years ago

Dear Imran

tan45 = tan (1 + 44) = tan1 + tan44 / 1 – tan1 tan44

1 – tan 1 tan44 = tan1 + tan44

(1 + tan1) (1 + tan44) = 2

similarly

(1 + tan2) (1 + tan43) = 2

Now

2 * 2* 2 * …...22 times * (1 + tan45)

= 2²³

Regards

Arun

In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.

trigonometry

1 Answer Available

Last Activity: 3 Years ago

Find the general solution of equation tan3∂=cot2∂
For all angles between -720 and +720

trigonometry

1 Answer Available

Last Activity: 4 Years ago

To prove : Cosec(45 degree - A)Cosec(45 degree + A) = 2SecA

trigonometry

1 Answer Available

Last Activity: 4 Years ago

Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)

trigonometry

1 Answer Available

Last Activity: 4 Years ago

WHAT IS THE LIMIT WHEN X TOWARDS TO 0 OF sin6x/5x ? lim𝑥→0 𝑠𝑖𝑛6𝑥/5𝑥

trigonometry

1 Answer Available

Last Activity: 4 Years ago

View all Questions

(1+tan1°)(1+tan2°)..................(1+tan45°)=2^nFind value of n?

Imran Khan

1 Answer

Arun

Other Related Questions on trigonometry

In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.

Find the general solution of equation tan3∂=cot2∂For all angles between -720 and +720

To prove : Cosec(45 degree - A)Cosec(45 degree + A) = 2SecA

Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)

WHAT IS THE LIMIT WHEN X TOWARDS TO 0 OF sin6x/5x ? lim𝑥→0 𝑠𝑖𝑛6𝑥/5𝑥

(1+tan1°)(1+tan2°)..................(1+tan45°)=2^n
Find value of n?

Find the general solution of equation tan3∂=cot2∂
For all angles between -720 and +720