(1+tan)(1+tan4α)=2 ,α ∈(0,π/16) then α is equal to

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(1+tan)(1+tan4α)=2 ,α ∈(0,π/16) then α is equal to

(1+tan)(1+tan4α)=2 ,α ∈(0,π/16) then α is equal to

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(1+tan)(1+tan4α)=2 ,α ∈(0,π/16) then α is equal to

(1+tan)(1+tan4α)=2 ,α ∈(0,π/16) then α is equal to

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