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[√(1+sin2A)+√(1-sin2A)]/√(1+sin2A)-√(1-sin2A)Given |tan A|≤1.|A| is an acute angle

[√(1+sin2A)+√(1-sin2A)]/√(1+sin2A)-√(1-sin2A)Given |tan A|≤1.|A| is an acute angle

Grade:11

1 Answers

Arun
25750 Points
5 years ago
Dear student
 
As |tan A|
Hence
A(0, pi/4)
Now
If we solve the given expression
SinA + cosA + sinA - cos A /[sinA + cosA -(sinA - cosA)]
= 2 sinA /2 cosA 
= Tan A

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