[√(1+sin2A)+√(1-sin2A)]/√(1+sin2A)-√(1-sin2A)Given |tan A|≤1.|A| is an acute angle
Shubham , 8 Years ago
Grade 11
Trigonometry> [√(1+sin2A)+√(1-sin2A)]/√(1+sin2A)-√(1-si...
1 Answers
Arun
Dear student
As |tan A|
Hence
A(0, pi/4)
Now
If we solve the given expression
SinA + cosA + sinA - cos A /[sinA + cosA -(sinA - cosA)]
= 2 sinA /2 cosA
= Tan A
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