Grade 11Trigonometry(√1-sin^2100)sec100=Pls reply fastWith a solution list Nidhi Bhat 10 Years agoGrade 11
Vikas TU10 Years ago(√1-sin^2100)sec100= can be written as:√(cos^2100)sec100 = k (let)k = cos100*sec100 = 1.i.e. k = + 1 and-cos100*sec100 = kk= -1 Now since sec100 is negative and thus -ve is multiplied with positive will always give a negative one.Hence k = +! iss being neglected.answer is k = -1.plz approve!