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(1 + sec A)/sec A = sin2A/(1-cos A) prove the following
Dear student (1+seca)/seca = sin2a/(1-cosa)Put seca = 1/cosa in LHS LHS Will simplify to cosa + 1 Multiply and divide with (1-cosa) (1-cos^2a)/(1-cosa)= sin2a/(1-cosa)
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