(1 + sec A)/sec A = sin2A/(1-cos A) prove the following

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Vikas TU · Answer

Dear student (1+seca)/seca = sin2a/(1-cosa) Put seca = 1/cosa in LHS LHS Will simplify to cosa + 1 Multiply and divide with (1-cosa) (1-cos^2a)/(1-cosa) = sin2a/(1-cosa)

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(1 + sec A)/sec A = sin2A/(1-cos A) prove the following

(1 + sec A)/sec A = sin2A/(1-cos A)

prove the following

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(1 + sec A)/sec A = sin2A/(1-cos A) prove the following

(1 + sec A)/sec A = sin2A/(1-cos A) prove the following

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(1 + sec A)/sec A = sin2A/(1-cos A)

prove the following