(1 + sec A)/sec A = sin2A/(1-cos A) prove the following
Pawan Prajapati , 4 Years ago
Grade 12
Trigonometry> (1 + sec A)/sec A = sin2A/(1-cos A) prove...
1 AnswersVikas TU
Last Activity: 4 Years ago
Dear student
(1+seca)/seca = sin2a/(1-cosa)
Put seca = 1/cosa in LHS
LHS Will simplify to
cosa + 1
Multiply and divide with (1-cosa)
(1-cos^2a)/(1-cosa)
= sin2a/(1-cosa)
(1+seca)/seca = sin2a/(1-cosa)
Put seca = 1/cosa in LHS
LHS Will simplify to
cosa + 1
Multiply and divide with (1-cosa)
(1-cos^2a)/(1-cosa)
= sin2a/(1-cosa)
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