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1+(cosA+cosB)cosC/1+(cosA-cosC)cosB=a^2+b^2/a^2-c^2

1+(cosA+cosB)cosC/1+(cosA-cosC)cosB=a^2+b^2/a^2-c^2

Grade:12

1 Answers

Arun
25750 Points
4 years ago
Dear student
 
Please put cosine law
 
cosA = b^2 + c^2 – a^2 / 2bc
 
You will get the answer.
 
Regards
Arun

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