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`        1-cosA+cosB-cos(A+B)/1+cosA-cosB-cos(A+B)=tanA/2×cotB/2`
one year ago

Arun
24493 Points
```							Dear Sonu  take the numerator of L.H.S 1-cosA+cosB-cos(A+B) simplifying 1-cosA = 2sin2  A/2 by half angle identity                                               cosB-cos(A+B) = 2sin(A/2)sin((A+2B)/2)  difference into product identity2sin2  A/2 + 2sin(A/2)sin((A+2B)/2)  by simple trigonometric identities  by further simplifying2sin(A/2)(sin A/2 + sin((A+2B)/2) now applying sum to product identity2sin(A/2)(2sin((A+B)/2)cosB/2-------------1and then take denominator 1+cosA-cosB-cos(A+B) similarly by half angle and sum into product identity we get2cos2  A/2 + 2cos(A/2)cos((A+2B)/2)by further simplifying2cos(A/2)(cos A/2 - cos((A+2B)/2) applying difference to product identity we get2cos(A/2)(2sin((A+B)/2)sinB/2---------------2now dividing 1 by 2we get  									tanA/2cotB/2
```
one year ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions