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Grade: 11
        
1-cosA+cosB-cos(A+B)/1+cosA-cosB-cos(A+B)=tanA/2×cotB/2
18 days ago

Answers : (1)

Arun
16262 Points
							
Dear Sonu
 
 

take the numerator of L.H.S 

1-cosA+cosB-cos(A+B) simplifying 1-cosA = 2sin2  A/2 by half angle identity

                                               cosB-cos(A+B) = 2sin(A/2)sin((A+2B)/2)  difference into product identity

2sin2  A/2 + 2sin(A/2)sin((A+2B)/2)  by simple trigonometric identities  

by further simplifying

2sin(A/2)(sin A/2 + sin((A+2B)/2) 

now applying sum to product identity

2sin(A/2)(2sin((A+B)/2)cosB/2-------------1

and then take denominator

 1+cosA-cosB-cos(A+B)

 similarly by half angle and sum into product identity we get

2cos2  A/2 + 2cos(A/2)cos((A+2B)/2)

by further simplifying

2cos(A/2)(cos A/2 - cos((A+2B)/2)

 applying difference to product identity we get

2cos(A/2)(2sin((A+B)/2)sinB/2---------------2

now dividing 1 by 2

we get

 

 

tanA/2cotB/2

18 days ago
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