# Find magnitude of work done in cyclic process in the attachment.... . Ans : π/4(p2-p1)(v2-v1).. .

Khimraj
3007 Points
4 years ago
work one is equal to area of PV graph
area of ellipse = $\pi$ab
a = (P2 – P1)/2
b = (V2 – V1)/2
so work done = ($\pi$/4)(P2-P1)(V2-V1)
Hope it clears...............................................................