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Grade: 12th pass
        
Find magnitude of work done in cyclic process in the attachment.... . Ans : π/4(p2-p1)(v2-v1).. . 
9 months ago

Answers : (1)

Khimraj
3008 Points
							
work one is equal to area of PV graph
area of ellipse = \piab
a = (P2 – P1)/2
b = (V2 – V1)/2
so work done = (\pi/4)(P2-P1)(V2-V1)
Hope it clears...............................................................
9 months ago
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