Find magnitude of work done in cyclic process in the attachment.... . Ans : π/4(p2-p1)(v2-v1).. .

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Khimraj · Answer

work one is equal to area of PV graph area of ellipse = ab a = (P2 – P1)/2 b = (V2 – V1)/2 so work done = ( /4)(P2-P1)(V2-V1) Hope it clears...............................................................

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Find magnitude of work done in cyclic process in the attachment.... . Ans : π/4(p2-p1)(v2-v1).. .

Find magnitude of work done in cyclic process in the attachment.... . Ans : π/4(p2-p1)(v2-v1).. .

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Find magnitude of work done in cyclic process in the attachment.... . Ans : π/4(p2-p1)(v2-v1).. .

Find magnitude of work done in cyclic process in the attachment.... . Ans : π/4(p2-p1)(v2-v1).. .

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