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Grade 12th passPhysical Chemistry

At 27°C the average total energy of O2 is approximately -

Profile image of Yamini
7 Years agoGrade 12th pass
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1 Answer

Profile image of Arun
7 Years ago
Total kinetic energy = n (3/2 RT0
where n = Number of moles of the gas
R = Gas constant
T = Absolute temperature
Molecular weight of methane,
CH4 = 12 + 4 * 1 = 16
∴ Number of moles of methane in 8.0 gm of methane
= 8.0/16.0 = 0.5
R = 8.314 joules/K/mole
T = 27 + 273 = 300 K
∴ Total kinetic energy of the molecules in 8.0 gm of methane at 27oC = InI * 3/2 RT
= 0.5 * 3/2 * 8.314 * 300 = 1870.65 joules
∴ Average kinetic energy = 1870.65/6.023 *1023 *0.5
= 6.21 * 10-21 joules/molecule