An electric heater of 1.08 kW is immersed in water. After the water has reached a temp. of 100 degree celcius , how much time will be required to produce 100g of steam?

Question

Bejoi Mathew · Answer

First, we calcuate the latent heat of vapourization which is nothing but the electric energy consumed. ie 2260 * 10 3 J/kg Heat required to convert 100g of steam = 226 * 10 3 J Power of the transmission heater= 1.08 kW Now, Power = Energy/time Therefore, Time = Energy/Power I HOPE I DID A GOOD JOB IN BREAKING UP THE QUESTION TO UNDERSTAND IT CONCEPTUALLY. PLEASE SOLVE FOR THE FINAL ANSWER YOURSELF. THANK YOU.

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An electric heater of 1.08 kW is immersed in water. After the water has reached a temp. of 100 degree celcius , how much time will be required to produce 100g of steam?

An electric heater of 1.08 kW is immersed in water. After the water has reached a temp. of 100 degree celcius , how much time will be required to produce 100g of steam?

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An electric heater of 1.08 kW is immersed in water. After the water has reached a temp. of 100 degree celcius , how much time will be required to produce 100g of steam?

An electric heater of 1.08 kW is immersed in water. After the water has reached a temp. of 100 degree celcius , how much time will be required to produce 100g of steam?

1 Answers

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