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An electric heater of 1.08 kW is immersed in water. After the water has reached a temp. of 100 degree celcius , how much time will be required to produce 100g of steam?
First, we calcuate the latent heat of vapourization which is nothing but the electric energy consumed.ie 2260 * 103J/kgHeat required to convert 100g of steam = 226 * 103JPower of the transmission heater= 1.08 kWNow, Power = Energy/timeTherefore, Time = Energy/PowerI HOPE I DID A GOOD JOB IN BREAKING UP THE QUESTION TO UNDERSTAND IT CONCEPTUALLY.PLEASE SOLVE FOR THE FINAL ANSWER YOURSELF.THANK YOU.
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