Arun
Last Activity: 7 Years ago
Dear Vaibhav
T1 = 500 K
T2 = 375 K
Q1 = heat absorbed = 600 k cal
i) efficiency (n) = 1 -(T2/T1) = 125/500 = 0.25
= 25%
ii) n = W/Q1
W = n* Q1 = 0.25 * 600 = 150 k cal
iii)-
W = Q1 - Q2
Q2 = Q1 - W
Q2 = 600 - 150 = 450 k cal
Regards
Arun (askIITians forum expert)