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A perfect carnot engine utilizes an ideal gas the source temperature is500K and sink temperature is 375K. If the engine takes 600k cal per cyclefrom the source, calculate(i) The efficiency of engine(ii) Work done per cycle(iii) Heat rejected to sink per cycle.

A perfect carnot engine utilizes an ideal gas the source temperature is500K and sink temperature is 375K. If the engine takes 600k cal per cyclefrom the source, calculate(i) The efficiency of engine(ii) Work done per cycle(iii) Heat rejected to sink per cycle.

Grade:11

1 Answers

Arun
25757 Points
5 years ago
Dear Vaibhav
 
T1 = 500 K
T2 = 375 K
Q1 = heat absorbed = 600 k cal
i) efficiency (n) = 1 -(T2/T1) = 125/500 = 0.25
 = 25%
ii) n = W/Q1
W = n* Q1 = 0.25 * 600 = 150 k cal
iii)- 
W = Q1 - Q2
Q2 = Q1 - W
Q2 = 600 - 150 = 450 k cal
 
Regards
Arun (askIITians forum expert)

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