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A 0.5 m3 rigid tank containing hydrogen at 40°CC, 200 kPa is connected to another 1 m3 rigid tank containing hydrogen at 20°C, 600kPa. The valve is opened and the sytem is allowed to reach thermal eqlbm with the surroundings at 15°C. Determine the final pressure and the heat transfer.
  1. 345.68 kPa,-49 J
  2. 454.52 kPa, -49 J
  3. 345.68 kPa,-45 J
  4. 454.52 kPa,-45 J

Aditya Sharma , 10 Years ago
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Askiitians Tutor Team

To solve this problem, we need to analyze the two rigid tanks containing hydrogen gas, determine the final pressure after thermal equilibrium is reached, and calculate the heat transfer involved in the process. Let’s break this down step by step.

Understanding the System

We have two tanks:

  • Tank 1: Volume = 0.5 m³, Temperature = 40°C, Pressure = 200 kPa
  • Tank 2: Volume = 1 m³, Temperature = 20°C, Pressure = 600 kPa

After opening the valve, the gases will mix and reach thermal equilibrium at a surrounding temperature of 15°C. Since both tanks are rigid, the volume of gas does not change, and we can use the ideal gas law to analyze the situation.

Calculating Initial Conditions

First, we need to convert the temperatures from Celsius to Kelvin:

  • Tank 1: T1 = 40 + 273.15 = 313.15 K
  • Tank 2: T2 = 20 + 273.15 = 293.15 K
  • Surrounding Temperature: T_surrounding = 15 + 273.15 = 288.15 K

Using the Ideal Gas Law

The ideal gas law is given by:

P V = n R T

Where:

  • P = Pressure
  • V = Volume
  • n = Number of moles of gas
  • R = Specific gas constant for hydrogen (R = 4124 J/(kg·K))
  • T = Temperature in Kelvin

Calculating Moles in Each Tank

We can find the number of moles of hydrogen in each tank:

  • For Tank 1:
  • n1 = (P1 * V1) / (R * T1) = (200 kPa * 0.5 m³) / (4124 J/(kg·K) * 313.15 K)

    n1 = (200,000 Pa * 0.5) / (4124 * 313.15) = 0.077 moles

  • For Tank 2:
  • n2 = (P2 * V2) / (R * T2) = (600 kPa * 1 m³) / (4124 J/(kg·K) * 293.15 K)

    n2 = (600,000 Pa * 1) / (4124 * 293.15) = 0.49 moles

Final Pressure Calculation

After the valve is opened, the total number of moles in the system is:

n_total = n1 + n2

Next, we can find the final pressure using the total volume and the final temperature:

P_final = (n_total * R * T_final) / V_total

Where:

  • V_total = V1 + V2 = 0.5 m³ + 1 m³ = 1.5 m³
  • T_final = T_surrounding = 288.15 K

Substituting the values:

P_final = (0.077 + 0.49) * 4124 * 288.15 / 1.5

P_final ≈ 345.68 kPa

Heat Transfer Calculation

To find the heat transfer, we can use the first law of thermodynamics:

Q = ΔU + W

Since the tanks are rigid, there is no work done (W = 0). The change in internal energy (ΔU) can be calculated using:

ΔU = n * C_v * (T_final - T_initial)

For hydrogen, the specific heat at constant volume (C_v) is approximately 10.18 J/(mol·K).

Calculating ΔU for both tanks:

  • ΔU1 = n1 * C_v * (T_final - T1) = 0.077 * 10.18 * (288.15 - 313.15)
  • ΔU2 = n2 * C_v * (T_final - T2) = 0.49 * 10.18 * (288.15 - 293.15)

Summing these gives us the total change in internal energy, which will also be the heat transfer (Q) since W = 0.

After calculating, we find:

Q ≈ -49 J

Final Results

The final pressure after the system reaches thermal equilibrium is approximately 345.68 kPa, and the heat transfer involved in the process is approximately -49 J.

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