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SIR PLESE SOLVE THIS THREE LIQUIDS P,Q,R ARE GIVEN. 4KG OF P AT 60 DEGREE C AND 1KG OF R AT 50 DEGREE C WHEN MIXED PRODUCE RESULTANT TEMPRATURE 55 DEGEE C.A MIXTURE OF 1KG OF P AT 60 DEGREE C AND 1KG OF Q AT 50 DEGREE C SHOWS TEMPERATURE 55 DEGREE C.WHAT WILL BE THE RESULTING TEMPERATURE WHEN 1KG OF Q AT 60 DEGEE C IS MIXED WITH 1KG OF R AT 50 DEGREE C?

SIR PLESE SOLVE THIS





THREE LIQUIDS P,Q,R ARE GIVEN. 4KG OF P AT 60 DEGREE C AND 1KG OF R AT 50 DEGREE C WHEN MIXED PRODUCE RESULTANT TEMPRATURE 55 DEGEE C.A MIXTURE OF 1KG OF P AT 60 DEGREE C AND 1KG OF Q AT 50 DEGREE C SHOWS TEMPERATURE 55 DEGREE C.WHAT WILL BE THE RESULTING TEMPERATURE WHEN 1KG OF Q AT 60 DEGEE C IS MIXED WITH 1KG OF R AT 50 DEGREE C?




Grade:11

1 Answers

Rohith Gandhi
24 Points
11 years ago

 

Dear Rohan,

case 1

4kg of P at 60 degree and 1 kg of R at 50 degree, resultant temp of mix = 55 degree

so, energy lost by P = energy gained by R and from calorimetry,

4XSpX(60-55)=1XSrX(55-50)   =>Sr = 4Sp

case 2

1kg of P at 60 degree and 1 kg of Q at 50 degree, resultant temp of mix = 55 degree

so, energy lost by P = energy gained by Q and from calorimetry,

1XSpX(60-55)=1XSqX(55-50)   =>Sq = Sp

from both above cases, we get, Sr = 4Sq

case 3

1kg of Q at 60 degree and 1 kg of R at 50 degree, resultant temp of mix = ?, let it be T

so, energy lost by Q = energy gained by R and from calorimetry,

1XSqX(60-T)=1XSrX(T-50)   => SqX(60-T)=4SqX(T-50) =>60-T = 4T - 200 =>5T = 260 => T = 260/5 = 52 degree

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Regards,

Askiitians Experts

Rohith Gandhi

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