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1. How much heat is required to change 10g ice at 0°C to steam at 100°C? Heat of fusion and heat of vaporization for water are 80cal/g and 540cal/g respectively. Specific heat of water is 1cal/g.
Q=mL+mcΔt+mL'
=10*80+10*1*(100-0)+10*540
=800+1000+5400
=7200cal.=7.2kcal
L=heat of fusion of ice
L'=heat of vapourisation of water
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