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A 1.0 kg bar of copper is heated at atmospheric pressure (1.01*10^5 N/m^2). If its temperature increases from 20 degree celcius to 50 degree celcius , calculate the change in its internal energy , alpha= 7.0*10^-6 per degree celcius, density = 8.92*10^3 kg/m^3 and specific heat capacity = 387 J/kg degree celcius.
let coefficient of volume expansion be gamma,P be atmospheric pressure, Q be change in internal energy, V be volume
Q=(387*1.0*30) -(P*gamma*V)
Please explain why did you use this formula??
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