MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        Two rectangular blocksn A and B of different metals have same length and same area of cross section.They are kept in such away that their cross sectional area touch each other.The temperature at one of A is 100degree celcius and that of B at y the other end is 0 degree celcius.If the ratio of their thermal conductivity is 1:3,then under steady state,the temperature of the junction in contact will be:
10 years ago

Answers : (1)

Ramesh V
70 Points
							

The amount of heat flowing per second is :

dQ/dt = KA.dT/L

K1:K2 = 1:3

let temp. of junction is T , as heal flow  rate is same

K1.(100-T) = K2.(T-0)

temp of junction is 25 C

--

Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and
we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best.

Regards,
Naga Ramesh
IIT Kgp - 2005 batch

10 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details