A 20N metal block is suspended by a spring balance. A beaker containing some water is placed on the weighing machine reads 36N. The spring balance is now lowered so that the block gets immersed in water. The spring balance now reads 16N. What will be the reading of the weighing machine ?

Question

Aman Bansal · Answer

dear kumar gaurav,

The spring balance reading decreases by (20-16) 4N when the block is immersed in water,

therefore the upthrust on the block is 4N.

according to the third law of motion it will exert an equal and opposite force

therefore the reading of the weighing machine will be

36+4 = 40 N

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AMAN BANSAL

Agniva Bagchi · Answer

initial reading =20N Final reading =16N decreased weight=20-16=4N(upward direction) now weight recorded by weighing machine=36N therefore the reading of the weighing machine will be 36+4=40N(downward direction)(acc.to newton’s third law) if you like the give a thums up!!!

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A 20N metal block is suspended by a spring balance. A beaker containing some water is placed on the weighing machine reads 36N. The spring balance is now lowered so that the block gets immersed in water. The spring balance now reads 16N. What will be the reading of the weighing machine ?

A 20N metal block is suspended by a spring balance. A beaker containing some water is placed on the weighing machine reads 36N. The spring balance is now lowered so that the block gets immersed in water. The spring balance now reads 16N. What will be the reading of the weighing machine ?

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