Grade 12th passPhysical Chemistry
Zns solubility in water 0.97g/l we mixed 2 moles of zn(N03)2 in 5L solution find new solubility of Zns
Zns solubility in water 0.97g/l we mixed 2 moles of zn(N03)2 in 5L solution find new solubility of Zns
2 Answers
Samyak Jain
Approved Tutor Answer7 Years agoSolubility of ZnS in water is 0.97 g/L = (0.97 / 97) mol/L = 0.01 M.
Solubility product Ksp = (0.01 M)(0.01 M) = 10–4 M2.
If we mix 2 moles of Zn(NO3)2 i.e. 2 moles of Zn2+ ions in 5L solution, the added concentration of Zn2+ ions
is 2/5 = 0.4 M.
ZnS(s) 
Zn2+(aq) + S2–(aq)
Conc. s + 0.4 s Ksp = (s + 0.4)(s)
s = [– 0.4 + 
] / 2 = [– 0.4 + 
] / 2
= [– 0.4 + 10–2 
] / 2 = – 0.2 + 10–2 
= – 0.2 + 0.20025 = 0.00025
s = 2.5 x 10–4 M = 2.5 x 97 x 10–4 g/L = 0.02425 g/L = new solubility of ZnS.
mbappe6789
Solubility of ZnS -0. 01M
Ksp-10-4
Ksp-(s+0.4) (s)
Ksp-0.4s (as 0.4is much greater than s... We consider only 0.4)
10-4 *1/0.4-s
s equal to 2.5*10-4
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