Arun
Last Activity: 4 Years ago
CuSO4•5H2O + 3NH3(g) = (NH4)2SO4 + 5H2O(l) + 0.5N2(g) + 0.5H2(g) + Cu
Change in Free Energy: ΔG(20C) = -159.9kJ (negative, so the reaction runs)
Change in Enthalpy: ΔH(20C) = -194.9kJ (negative, so the reaction is exothermic)
However, it is possible, with more ammonia gas, to get:
CuSO4•5H2O + 6NH3(g) = (NH4)2SO4•3NH3 + 5H2O(l) + 0.5N2(g) + 0.5H2(g) + Cu
Change in Free Energy: ΔG(20C) = -145.5kJ (negative, so the reaction runs)
Change in Enthalpy: ΔH(20C) = -303.3kJ (negative, so the reaction is exothermic)
(NH4)2SO4•3NH3 is “ammonium sulfate – ammonia complex 1:3”
