Kushagra Madhukar
Last Activity: 4 Years ago
Dear student,
NaCl is a volatile solid. Less volatile liquid H2SO4 displaces the
more volatile sodium chloride and hence there is no changed in oxidation state. Due to this it becomes a simple displacement reaction as
NaCl + H2SO4 → NaHSO4 +HCl
In case of NaBr, Br- acts as reducing agent fr H2SO4 and the sulphuric acid is reduced to sulphr ioxide by bromide ion which itself gets oxideised to give bromine free molecule.
2NaBr + 2H2SO4 → NaHSO4 + Br2 + SO2 + 2H2O
Hope it helps.
Thanks and regards,
Kushagra