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Grade 10Physical Chemistry

When a metal is irradiated with light of frequency 4.0×10*16s*-1the photo eelectrons emmited had sixtimes the KE as the KE of photo electron emmited when the metal was irradiated with light of frequency 2.0×10*16 s*-1 .calculate the critical frequency of the metal

Profile image of Gopi
9 Years agoGrade 10
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1 Answer

Profile image of Aayush Baliyan
9 Years ago
Frequency 1=4.0×10*16s*-1Let K.E. 1=6KFrequency 2=2.0×10*16 s*-1Let K.E. 2=KTherefore,6K/K=(4.0×10*16s*-1)-v/(2.0×10*16 s*-1)-vThis will give v= 1.6×10*16s*-1