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Grade upto college level Physical Chemistry

When 1-pentyne (A) is treated with 4 N alcoholic KOH at 17S°C, it is converted slowly into an equilibrium mixture of 1.3% I-pentyne (A), 95.2% 2-pentyne (B) and 3.5% of 1,2- pentadiene (C). The equilibrium was maintained at 175°C. Calculate AGO for the following equilibria :
B ⇌ A ∆Go1 =? B ⇌ C ∆Go2 =?
From the calculated value of ∆Go1 and ∆Go2 indicate the order of stability of (A), (B) and (C). Write a reasonable reaction mechanism showing all intermediates leading to (A), (B) and (C).

Profile image of Shane Macguire
12 Years agoGrade upto college level
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1 Answer

Profile image of Deepak Patra
12 Years ago
Hello Student,
Please find the answer to your question
∆G° = -2.303RT log [Product]/[Reactant]
Calculation of ∆G values :
Thus for the equilibrium B ⇌ A
Go1 = (-2.303 * 8.314 * 448) log 1.3/95.2
Or Go1= 15.992 kJ mole-1
Similarly for the equilibrium B ⇌C
Go2= (-2.303 * 8.314 * 448) log 3.5/95.2
Or Go1= 12.312 kJ mole-1
Similarly for equilibrium, A ⇌ C
Go3= - 8.314 * 448 * 2.303 * log10 3.5/1.3 = - 3.688 kJ mole-1
Hence, we have that
B ⇌ A, Go1= + 15.992 kJ mole-1
B ⇌C, Go2= + 12.312 kJ mole-1
B ⇌ C, Go3= - 3.688 kJ mole-1
Thus, the correct order of stability, B > C > A
NOTE : Mechanism of isomerisation
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jitender
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