×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
When 1 mole A reacts with ½ mole of B 2 (A + ½B 2 = AB), 100 Kcal heat is liberated and when 1 mole of A reacts with 2 mole of B 2 ( A + 2B 2= AB 4 ), 200 Kcal heat is liberated . When1 mole of A is completely reacted with excess, of B 2 to form AB as well as AB 4 , 140 Kcal heat is liberated calculate the mole of B 2 used.
When 1 mole A reacts with ½ mole of B2 (A + ½B2 = AB), 100 Kcal heat is liberated and when 1 mole of  A reacts with 2 mole of B2( A + 2B2= AB4), 200 Kcal heat is liberated . When1 mole of A is completely reacted with excess, of B2 to form AB as well as AB4, 140 Kcal heat is liberated calculate the mole of B2 used.

```
4 years ago

Vikas TU
14146 Points
```							(A + ½B2 = AB) => 100kcal(A +2B2 = AB4) => 200kcalAdding both chemical eqns. we get,2A + 5/2 B2  -------->  1/2AB   +  1/2AB4ORA + 5/4 B2  -------->  1/4AB   +  1/4AB4Total Energy = 100 + 200 = 300 kcal. For original reacn. The energy releases = 140 kcal.Now for 140 kcal let x be the moles of B2 used then,then x = > 140 x 5/4 / 300 = > 7/12 moles.
```
4 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Physical Chemistry

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 141 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions