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What will be the resulting normality of NaCl solution formed on mixing 200ml of decimolar NaOH with 40ml of semimolar HCl?

What will be the resulting normality of NaCl solution formed on mixing 200ml of decimolar NaOH with 40ml of semimolar HCl?

Grade:11

1 Answers

Sujit Kumar
111 Points
5 years ago
Decimolar solution means 0.1M
Semimolar solution means 0.5M
 
NaOH + HCl → NaCl + H2O
 
No. Of millimoles of NaOH = 200*0.1 = 20
No. Of millimoles of HCl = 40*0.5 = 20
 
→ No. Of millimoles of NaCl formed = 20
→ Normality = (no. Of millimoles * n-factor)/volume of sol.(in mL)
→ Normality = (20*1)/240                           (240mL is the total volume i.e 200+40, 1 is the n-factor of NaCl)
→ Normality = 0.0833 N
 
Ans: 0.0833 N

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