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what volume of decinormal k2cr2o7 solution would be needed to convert 1.19g of tin to stannic chloride in acidic medium

what volume of decinormal k2cr2o7 solution would be needed to convert 1.19g of tin to stannic chloride in acidic medium

Grade:11

2 Answers

Bhavya
askIITians Faculty 1281 Points
7 years ago
Dear student
This is an example of redox titration.
SnCl2+ K2Cr2O7+ 14HCl → 3SnCl4+ 2CrCl3+ 2KCl + 7H2O
Now, we know the law of equivalence i.e.
equivalence of K2Cr2O7 = equivalence of SnCl2
N*V of K2Cr2O7 = equivalence of SnCl2 => mass/equivalent mass = (1.19 g/Molecular mass)*n-factor
On solving you will get your answer.Hope this helps
Sarthak
11 Points
7 years ago
It is tin to stannic chloride not stannous to stannic chloride so sn changes to sncl4 and so n-factor is 4

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