Grade 11Physical Chemistry
What volume of CO2 at NTP will be liberated by the action of 100mL of 0.2 N HCL on CaCO3?
1 Answer
varun
HELLO,
Understand the reaction first
CaCO3 + 2HCl -----------> CaCl2 + CO2 + H2O
we know that
Normality = gram equivalent/volume
0.2N = gram eq / 0.100
so ,
gram equivalent of HCl = 0.2 X 0.100
= 0.02
=> gram equivalent of HCl = moles of HCl = 0.02 moles
So moles of CaCO3 = 0.02/2
= 0.01 moles
so 1 mole = 22.4 litres
0.01 moles = 0.224 litres
THANK YOU
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