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Grade 11Physical Chemistry

what volume of chlorine at stp is required to liberate all iodine from 200ml of 0.2M KI solution

Profile image of karan patel
9 Years agoGrade 11
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1 Answer

Profile image of Bristi Mukherjee
9 Years ago
2KI + Cl2  ------->  2KCl + I2
Moles of KI reacted = 0.2 x 200/1000 = 0.04 moles of KI
According to reaction stoichiometry, 0.04moles of KI will react with 0.04/2 moles Cl2  to liberate I2 completely.
At STP, 1 mole Cl2 corresponds to 22.4L
So, 0.02 moles of Cl2  corresponds to 0.448L
 
Hence 0.448L of Cl2 will be required to liberate I2 completely from the given solution

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