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`        What percentage of Fe+3 is present in Fe0.93O???????????`
2 years ago

Chhavi Jain
92 Points
```							Dear Student,  We know that the compound contains the mixture of Fe2+ and Fe+3  ions , but we don’t know how much each of them is present . The trick we will use to solve this question is charge balancing . Let us say that we have 100 moles of the compound .So, there will be 93 ions of Fe2+  and  Fe3+     and    100 ions of O2- ,Since the compound is neutral so, the (-2) charge of the oxygen must be balanced with the overall charge of iron ions.  Let us say that we have x  ions of iron (II)  and  y  ions of iron(III) . Now ,  x+y = 93          ….............eq.(i)also, total positive charge = total negative charge x (+2)  +  y (+3) = 100 (-2)                       ….............. eq.(ii) solving eq.(i)  and eq.(ii) we get ;x= 79   and y=14 so, we hav 14 Fe3+  ions  and total ions in the compound is 193. So, the percent composition of Fe3+  ions in the compound is = ( 14 Fe3+  ions / 193 total ions ) * 100 =7.25%
```
2 years ago
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