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What is the wavelenth of light emitted when the electron in ahydrogen atom undergoes transition from an energy level with N=4 to an energy level with N=2?
According to Balmer formulaWave no = RH [1/n12 – 1/n22]Here n1 = 2 , n2 = 4, RH = 109678Putting these values in the equation we getWave number =109678(1/22 - ¼2) = 109678 x 3/16Also λ = 1/ wave numberTherefore λ = 16 / 109678 x 3 = 486 nm
According to Balmer formula
Wave no = RH [1/n12 – 1/n22]
Here n1 = 2 , n2 = 4, RH = 109678
Putting these values in the equation we get
Wave number =109678(1/22 - ¼2) = 109678 x 3/16
Also λ = 1/ wave number
Therefore λ = 16 / 109678 x 3 = 486 nm
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