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C4H10 + 6.5 O2= 4CO2 + 5 H2O
So, four moles of CO2 for each mole of Butane.
Molar mass of Butane = (4x12) + (10 x 1) = 58g/mol
Moles of Butane = 290/58 = 5 mol
So, if we're assuming 24 L per mole of gas then 120 L of Butane.
Which gives 480 L ofCO2
Although other molar gas volumes are available as it is temperature dependent
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