What is the volume of 0.1N HCl required to react completely with 1.0g of pure calcium carbonate

Dear student ......for complete reaction the number of equivalents of the reactants must be same ...so equivalents of HCl = equivalents of CaCO3 ........Equivalents of HCl = N×V =0.1 × V ......Equivalent of CaCO3 = Wt / equivalent wt = 1/50 ( eq. Wt = mol wt./ valency factor = 100/2=50).....Hence , 0.1×V=0.02 .....therefore , V = 0.2 ltr or 200 ml.....With regards ...mahima...( Askiitians forum expert )