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What is the volume occupied by 1 mole of H 2 O (l) at STP ?
Given density =1 gm/ml =1gm /0.001 Las we know1 mole of water has 6.022×10^23 moleculesi.e., 18 gm of water has 6.022×10^23 moleculesso 1 gm of water has 6.022×10^23/18 molecules = 0.3345×10^23 moleculesso 0.3345×10^23 molecules in 0.001 Lso 1 molecule will occupy 0.001/0.3345×10^23 L =0.002989×10^-23 L
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