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Grade 12Physical Chemistry

What is the reduction potential of zinc if the solution of zinc ion is diluted 10times

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8 Years agoGrade 12
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ApprovedApproved Tutor Answer1 Year ago

To understand the reduction potential of zinc when its ion solution is diluted tenfold, we need to delve into the concept of reduction potential and how concentration affects it. The reduction potential, often expressed in volts, indicates how readily a species gains electrons and is reduced. For zinc, the half-reaction can be represented as follows:

The Standard Reduction Potential of Zinc

The standard reduction potential (E°) for the zinc ion (Zn²⁺) to zinc metal (Zn) is approximately -0.76 V. This value is measured under standard conditions, which include a concentration of 1 M for all species involved, a temperature of 25°C, and a pressure of 1 atm.

Impact of Dilution on Reduction Potential

When we dilute a solution, we change the concentration of the ions present. In this case, diluting the zinc ion solution by a factor of ten means that the concentration of Zn²⁺ ions decreases from 1 M to 0.1 M. According to the Nernst equation, the reduction potential can be adjusted based on the concentration of the ions in solution:

  • The Nernst equation is given by: E = E° - (RT/nF) * ln(Q)
  • Where:
    • E = reduction potential under non-standard conditions
    • = standard reduction potential
    • R = universal gas constant (8.314 J/(mol·K))
    • T = temperature in Kelvin
    • n = number of electrons transferred in the half-reaction
    • F = Faraday's constant (96485 C/mol)
    • Q = reaction quotient, which depends on the concentrations of the reactants and products

Calculating the New Reduction Potential

For the reduction of zinc, the half-reaction involves the transfer of two electrons (n = 2). When the concentration of Zn²⁺ is diluted to 0.1 M, we can calculate the new reduction potential:

  • At standard conditions (25°C or 298 K), the Nernst equation simplifies to:
  • E = E° - (0.0592/n) * log(Q)
  • For our reaction, Q is the concentration of Zn²⁺ ions, which is 0.1 M:
  • Thus, Q = 1 / [Zn²⁺] = 1 / 0.1 = 10.

Now substituting the values into the equation:

  • E = -0.76 V - (0.0592/2) * log(10)
  • E = -0.76 V - (0.0296) * 1
  • E = -0.76 V - 0.0296 V
  • E = -0.7896 V

Final Thoughts

The reduction potential of zinc when the solution of zinc ions is diluted ten times to 0.1 M is approximately -0.79 V. This illustrates how dilution affects the electrochemical behavior of ions in solution, leading to a more negative reduction potential. Understanding these concepts is crucial in fields like electrochemistry and materials science, where the behavior of metals and their ions plays a significant role in various applications.