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What is the oxidation state of fe in the product formed when acidified potassium ferrocyanide (k4[fe(cn)6]) is treated with hydrogen peroxide?
The oxidation number of Fe in K4Fe(CN)6 can be calculated as follows, 4(+1) + x + 6(-1) = 0 Hence x = +2
The oxidation number of Fe in K4Fe(CN)6 can be calculated as follows,
4(+1) + x + 6(-1) = 0
Hence x = +2
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