Physical Chemistrywhat is the no. of wave in fourth orbit-a.4 b.5 c.0 d.1 Tanusri Bose 8 Years agoGrade
ArunApproved Tutor Answer8 Years agoNo.of waves = circumference of electron orbit / wave length =2πr /λ λ=h /mv No.of waves =2π/h *(mvr) The angular momentum in 4th orbit mvr = nh/2π = 4h/2π Substitute the mvr value No.of waves=2π/h* 4h/2π =4