Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
WHAT IS THE EMPIRICAL FORMULAE OF A COMPOUND 0.2801 GRAM OF WHICH GAVE ON COMPLETE COMBUSTION 0.9482 GRAM OF CARBON DIOXIDE AND 0.1939 GRAM OF WATER
From unitary method,If 44g of CO2 has 12 g carbon then 0.9482 gm Carbon Dioxide would contain => 12/44 * 0.9482 => 0.2586 gms of CarbonAnd 0.1939 of Water would contain => 2/18 * 0.1939=> 0.021 gm Hydrogen. Now carbon moles = 0.2586/12 = 0.021H moles= 0.021Hence the formulae is:C1H1 => (CH)
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -