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Grade 11Physical Chemistry

What is the debroglie wavelength of electron in hydrogen atom moving in an orbit having maximum magnetic quantum no =+2

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8 Years agoGrade 11
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ApprovedApproved Tutor Answer1 Year ago

To find the de Broglie wavelength of an electron in a hydrogen atom with a maximum magnetic quantum number of +2, we first need to understand a few key concepts related to quantum mechanics and the properties of electrons in atoms.

Understanding Quantum Numbers

In quantum mechanics, electrons in an atom are described by a set of quantum numbers. The magnetic quantum number (ml) indicates the orientation of the orbital in which the electron resides. For a maximum magnetic quantum number of +2, this corresponds to a d-orbital, specifically the 3d orbital in the case of hydrogen, which has a principal quantum number (n) of 3.

Calculating the de Broglie Wavelength

The de Broglie wavelength (λ) of a particle is given by the formula:

λ = h / p

where:

  • h is Planck's constant (approximately 6.626 x 10-34 Js),
  • p is the momentum of the electron.

Finding the Momentum of the Electron

The momentum (p) of an electron can be expressed as:

p = mv

where:

  • m is the mass of the electron (approximately 9.11 x 10-31 kg),
  • v is the velocity of the electron.

To find the velocity of the electron in the hydrogen atom, we can use the formula for the velocity of an electron in a given orbit:

v = Z * e2 / (4 * π * ε0 * h)

For hydrogen (Z = 1), this simplifies to:

v = e2 / (4 * π * ε0 * h)

Substituting Values

Now, let's substitute the known values:

  • e (elementary charge) ≈ 1.602 x 10-19 C,
  • ε0 (vacuum permittivity) ≈ 8.854 x 10-12 C2/(N·m2),
  • h ≈ 6.626 x 10-34 Js.

After calculating the velocity, we can find the momentum:

p = m * v

Calculating the Wavelength

Finally, we substitute the momentum back into the de Broglie wavelength formula:

λ = h / p

By performing these calculations step-by-step, you will arrive at the de Broglie wavelength for the electron in the hydrogen atom with a maximum magnetic quantum number of +2. This wavelength is crucial for understanding the wave-particle duality of electrons and their behavior in atomic structures.

Final Thoughts

In summary, the de Broglie wavelength provides insight into the quantum behavior of electrons. By understanding the relationships between quantum numbers, momentum, and wavelength, we can better appreciate the fundamental principles of quantum mechanics that govern atomic structure.