Grade 11Physical Chemistry
What is relation b/w mole fraction of solute and molality of a solution?
1 Answer
Sommay shivangi
Mass of solution =na.Ma+ nb.MbVolume= mass/ density= (na.Ma+nb.Mb)/dMolarity=(no. Of moles of solute*1000)/volume of solutionM= (nb*1000)/(na.Ma+nb.Mb)/dM= (nb*1000*d)/(na.Ma+nb.Mb)Div. By na+nb=> M=(xb*1000*d)/(xa.Ma+xb.Mb)Where, na- no.of moles of solventnb- no. Of moles of soluteMa- molecular mass of solventMb-molecular mass of soluted- densityxa- mole fraction of solventxb- mole fraction of soluteM- molarity of solution
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