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what is number of electrons involved in the reaction when 0.1 mole NH3 dissolved in water?

karunyaa , 10 Years ago
Grade 12th pass
anser 1 Answers
Sunil Kumar FP

Last Activity: 10 Years ago

NH3 +H2O ----NNH4OH

no of electron involved in single reaction is 1.therefore in .1 mole=.1*Na=6.023*10^22

thanks and regards
sunil kr
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