Grade 12th passPhysical Chemistry

What are the units of rate constant for the first order reaction?

Mayank Ranka

5 Years agoGrade 12th pass

9 Answers

Rituraj Tiwari

5 Years ago

LetRbe the rate of reaction.
For first order reaction,
R=K[A]1
⇒K=R[A]^−1
Whereas,Kand[A]are rate constant and initial concentration of reactant respectively.
Therefore,
Unit of rate constant=(molL−1)^(1−n)sec−1
For first order reaction,
n=1
Unit of rate constant=sec−1
Hence the unit of rate constant for first order reaction issec−1.

Vikas Amritiya

5 Years ago

Dear student

Let R be the rate of reaction.

For first order reaction,

R=K[A]1

⇒K=R[A]−1

Whereas, K and [A] are rate constant and initial concentration of reactant respectively.

Therefore,

Unit of rate constant =(molL−1)1−nsec−1

For first order reaction,

n=1

Unit of rate constant =sec−1

Hence the unit of rate constant for first order reaction is sec−1.

adilakshmigogada 27

5 Years ago

Let R be the rate of reaction.

For first order reaction,

R=K[A]1

⇒K=R[A]−1

Whereas, K and [A] are rate constant and initial concentration of reactant respectively.

Therefore,

Unit of rate constant =(molL−1)1−nsec−1

For first order reaction,

n=1

Unit of rate constant =sec−1

Hence the unit of rate constant for first order reaction is sec−1

adilakshmigogada 27

5 Years ago

Let R be the rate of reaction.

For first order reaction,

R=K[A]1

⇒K=R[A]−1

Whereas, K and [A] are rate constant and initial concentration of reactant respectively.

Therefore,

Unit of rate constant =(molL−1)1−nsec−1

For first order reaction,

n=1

Unit of rate constant =sec−1

Hence the unit of rate constant for first order reaction is sec−1/

adilakshmigogada 27

5 Years ago

Let R be the rate of reaction.

For first order reaction,

R=K[A]1

⇒K=R[A]−1

Whereas, K and [A] are rate constant and initial concentration of reactant respectively.

Therefore,

Unit of rate constant =(molL−1)1−nsec−1

For first order reaction,

n=1

Unit of rate constant =sec−1

Hence the unit of rate constant for first order reaction is sec−1

‘/

adilakshmigogada 27

5 Years ago

Let R be the rate of reaction.

For first order reaction,

R=K[A]1

⇒K=R[A]−1

Whereas, K and [A] are rate constant and initial concentration of reactant respectively.

Therefore,

Unit of rate constant =(molL−1)1−nsec−1

For first order reaction,

n=1

Unit of rate constant =sec−1

Hence the unit of rate constant for first order reaction is sec−1

]’/

adilakshmigogada 27

5 Years ago

Let R be the rate of reaction.

For first order reaction,

R=K[A]1

⇒K=R[A]−1

Whereas, K and [A] are rate constant and initial concentration of reactant respectively.

Therefore,

Unit of rate constant =(molL−1)1−nsec−1

For first order reaction,

n=1

Unit of rate constant =sec−1

Hence the unit of rate constant for first order reaction is sec−1

/,.

adilakshmigogada 27

5 Years ago

Let R be the rate of reaction.

For first order reaction,

R=K[A]1

⇒K=R[A]−1

Whereas, K and [A] are rate constant and initial concentration of reactant respectively.

Therefore,

Unit of rate constant =(molL−1)1−nsec−1

For first order reaction,

n=1

Unit of rate constant =sec−1

Hence the unit of rate constant for first order reaction is sec−1

,.,.

irshad hussain

5 Years ago

k is the first-order rate constant, which has units of 1/s. The method of determining the order of a reaction is known as the method of initial rates. The overall order of a reaction is the sum of all the exponents of the concentration terms in the rate equation.