Question icon
Grade 9Physical Chemistry

Water of mass 75g at 100 degree Celsius id added to ice of mass 20 g at -15 degree Celsius. What will be the resultant temperature???
( Latent heat of ice is 80C/g and specific heat of ice is 0.5C/g/K)

Profile image of Shinjini Ghosh
8 Years agoGrade 9
Answers icon

1 Answer

Profile image of Khimraj
ApprovedApproved Tutor Answer8 Years ago
Let final temp is T
then heat loss = heat gain
75*1*(100 – T) = 20*0.5*15 + 20*80 + 20*1*(T-0)
5750 = 95T
Then T = 60.5oC
Hope it clears.