Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Volume of CO2 obtained at STP by the complete decomposition of 98.5 g Na2CO3 is
moles of Na2CO3 = 98.5/106 = 0.9292 mol.Na2CO3 ----------> Na2O + CO2moles of CO2 = 0.9292 mol {From mole 1 analysis}Volume = 0.9292*22.4 = 20.81 litre.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -