Vikas TU
Last Activity: 8 Years ago
Degree of dissociation,
1 + a = Mthe./Mobs. => 92/(2*25.67)
a = 1.791 – 1 => 0.791
Now the reaction is given as:\
N2O4 ----------------> 2NO2
T=0 P
T=Teq. P(1-a) 2Pa
Kp = (2Pa)^2/P(1-a)
= 4P^2a^2/P(1-a)
= 4Pa^2/(1-a)
put P= 1 atm and a = 0.791
we get,
Kp = 4*(0.791)^2/(1-0.791) => 11.9714 atm.