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Grade: 12
        VD of N2O4 which dissociates is 25.67 at 100 °c and pressure of 1 atm. calculate degree of dissociation and Kp for this.
one year ago

Answers : (1)

Vikas TU
6874 Points
							
Degree of dissociation,
1 + a = Mthe./Mobs. => 92/(2*25.67)
a = 1.791 – 1 => 0.791
 
Now the reaction is given as:\
 
                     N2O4        ---------------->         2NO2
        T=0         P
        T=Teq.    P(1-a)                                    2Pa
Kp = (2Pa)^2/P(1-a)
     = 4P^2a^2/P(1-a)
    = 4Pa^2/(1-a)
put P= 1 atm and a = 0.791
we get,
Kp = 4*(0.791)^2/(1-0.791) => 11.9714 atm.
one year ago
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