To determine the molecular mass of the non-volatile non-electrolyte solid added to benzene, we can use Raoult's Law, which relates the vapor pressure of a solution to the vapor pressure of the pure solvent and the mole fraction of the solvent in the solution. Let's break this down step by step.
Understanding Raoult's Law
Raoult's Law states that the vapor pressure of a solvent in a solution (P_solution) is equal to the vapor pressure of the pure solvent (P_pure) multiplied by the mole fraction of the solvent (X_solvent) in the solution:
P_solution = P_pure × X_solvent
Given Data
- P_pure (vapor pressure of pure benzene) = 640 mm Hg
- P_solution (vapor pressure of the solution) = 600 mm Hg
- Mass of solid = 2.175 g
- Mass of benzene = 39.0 g
Calculating the Mole Fraction of Benzene
First, we need to find the mole fraction of benzene in the solution. We can rearrange Raoult's Law to find X_solvent:
X_solvent = P_solution / P_pure
Substituting the values:
X_solvent = 600 mm Hg / 640 mm Hg = 0.9375
Finding the Mole Fraction of the Solid
The mole fraction of the solid (X_solid) can be calculated as:
X_solid = 1 - X_solvent
So:
X_solid = 1 - 0.9375 = 0.0625
Calculating Moles of Benzene
Next, we need to calculate the number of moles of benzene. The molar mass of benzene (C6H6) is approximately 78.11 g/mol. Using the formula:
moles = mass / molar mass
We find:
moles of benzene = 39.0 g / 78.11 g/mol ≈ 0.499 moles
Relating Moles to Mole Fraction
The mole fraction of the solid can also be expressed in terms of moles:
X_solid = moles of solid / (moles of solid + moles of benzene)
Let the number of moles of the solid be n. Then:
0.0625 = n / (n + 0.499)
Solving for Moles of the Solid
Cross-multiplying gives:
0.0625(n + 0.499) = n
Expanding this, we get:
0.0625n + 0.031125 = n
Rearranging terms leads to:
n - 0.0625n = 0.031125
0.9375n = 0.031125
Thus:
n ≈ 0.0332 moles
Calculating the Molecular Mass of the Solid
Now, we can find the molecular mass (M) of the solid using the formula:
M = mass of solid / moles of solid
Substituting the values:
M = 2.175 g / 0.0332 moles ≈ 65.4 g/mol
Final Result
Therefore, the molecular mass of the non-volatile non-electrolyte solid is approximately 65.4 g/mol.